Termination w.r.t. Q of the following Term Rewriting System could be proven:
Q restricted rewrite system:
The TRS R consists of the following rules:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
zWadr(cons(X), cons(Y)) → cons(app(Y, cons(X)))
prefix(L) → cons(nil)
Q is empty.
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
zWadr(cons(X), cons(Y)) → cons(app(Y, cons(X)))
prefix(L) → cons(nil)
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
zWadr(cons(X), cons(Y)) → cons(app(Y, cons(X)))
prefix(L) → cons(nil)
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
zWadr(cons(X), cons(Y)) → cons(app(Y, cons(X)))
Used ordering:
Polynomial interpretation [25]:
POL(app(x1, x2)) = x1 + x2
POL(cons(x1)) = 2 + x1
POL(from(x1)) = 2 + x1
POL(nil) = 0
POL(prefix(x1)) = 2 + x1
POL(zWadr(x1, x2)) = 2·x1 + x2
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
prefix(L) → cons(nil)
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
prefix(L) → cons(nil)
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
app(nil, YS) → YS
app(cons(X), YS) → cons(X)
from(X) → cons(X)
prefix(L) → cons(nil)
Used ordering:
Polynomial interpretation [25]:
POL(app(x1, x2)) = 2 + 2·x1 + x2
POL(cons(x1)) = 1 + 2·x1
POL(from(x1)) = 2 + 2·x1
POL(nil) = 0
POL(prefix(x1)) = 2 + x1
POL(zWadr(x1, x2)) = x1 + 2·x2
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
Q restricted rewrite system:
The TRS R consists of the following rules:
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
Q is empty.
The following Q TRS is given: Q restricted rewrite system:
The TRS R consists of the following rules:
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
Q is empty.
The following rules can be removed by the rule removal processor [15] because they are oriented strictly by a polynomial ordering:
zWadr(nil, YS) → nil
zWadr(XS, nil) → nil
Used ordering:
Polynomial interpretation [25]:
POL(nil) = 1
POL(zWadr(x1, x2)) = 2 + 2·x1 + 2·x2
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RRRPoloQTRSProof
↳ QTRS
↳ RisEmptyProof
Q restricted rewrite system:
R is empty.
Q is empty.
The TRS R is empty. Hence, termination is trivially proven.